Расчет: Qf05v6 - 1

V_₂ =
V_₁* (1+ β* Δ__t)

V_₂ = V_₁* (1+ β* Δ__t) $V_{2}$ = $V_{1}\cdot (1+\beta\cdot \Delta_{t})$

V_₂ = V_₁+ Δ__t* β* V_₁ $V_{2}$ = $V_{1}+\Delta_{t}\cdot \beta\cdot V_{1}$

V_₂ = V_₁+ V_₁* Δ__t* β $V_{2}$ = $V_{1}+V_{1}\cdot \Delta_{t}\cdot \beta$