Расчет: QyTrYZ - 1

2* h* n* cos(β) =
k* λ

2* h* n* cos(β) = k* λ $2\cdot h\cdot n\cdot cos(\beta)$ = $k\cdot \lambda$

h =

k* λ

/ 2/ n/ cos(β)

$h$ = $\frac{k\cdot \lambda}{2\cdot n\cdot cos(\beta)}$

h =

0.5* k* λ

/ cos(β)/ n

$h$ = $\frac{0.5\cdot k\cdot \lambda}{cos(\beta)\cdot n}$