Расчет: gMruxB - 1

2* h* n* cos(β) =

( 2* k+1)* λ

/ 2

2* h* n* cos(β) =

( 2* k+1)* λ

/ 2

$2\cdot h\cdot n\cdot cos(\beta)$ = $\frac{(2\cdot k+1)\cdot \lambda}{2}$

2* h* n* cos(β) = k* λ+

/ 2

$2\cdot h\cdot n\cdot cos(\beta)$ = $k\cdot \lambda+\frac{\lambda}{2}$

h =

( k* λ+

/ 2

)

/ 2/ n/ cos(β)

$h$ = $\frac{k\cdot \lambda+\frac{\lambda}{2}}{2\cdot n\cdot cos(\beta)}$

h =

0.5* λ* ( 2* k+1)

/ 2/ n/ cos(β)

$h$ = $\frac{0.5\cdot \lambda\cdot (2\cdot k+1)}{2\cdot n\cdot cos(\beta)}$

h =

0.25* λ* ( 2* k+1)

/ n/ cos(β)

$h$ = $\frac{0.25\cdot \lambda\cdot (2\cdot k+1)}{n\cdot cos(\beta)}$

h =

0.5* k* λ

/ cos(β)/ n

0.25* λ

/ cos(β)/ n

$h$ = $\frac{0.5\cdot k\cdot \lambda}{cos(\beta)\cdot n}+\frac{0.25\cdot \lambda}{cos(\beta)\cdot n}$