Расчет: qjMQGZ - 1

r  = 
 n^2* 0.528* 10^(-10)
r =  n^2* 0.528* 10^(-10)$$r$$ = $$n^{2}\cdot 0.528\cdot 10^{(-10)}$$
r =  0.0000000000528* n^2$$r$$ = $$0.0000000000528\cdot n^{2}$$
r =  5.28* E- 11* n^2$$r$$ = $$5.28\cdot E-11\cdot n^{2}$$
r =  0.0000000000528* n^2$$r$$ = $$0.0000000000528\cdot n^{2}$$
r =  5.28* n^2* 10^(-11)$$r$$ = $$5.28\cdot n^{2}\cdot 10^{(-11)}$$