Расчет: vnX9Rf - 1
S_n =
S_0+(1+
)
S_0+(1+
| p |
| / 100 |
|
S_n = S_0+(1+
)$$S_{n}$$ = $$S_0+(1+\frac{p}{100})$$
| p |
| / 100 |
S_n = S_0+1+
$$S_{n}$$ = $$S_0+1+\frac{p}{100}$$
| p |
| / 100 |
S_n = S_0+1+ 0.01* p$$S_{n}$$ = $$S_0+1+0.01\cdot p$$