Расчет: z69k2Y - 1
Φ =
BS* cos(a)
BS* cos(a)
|
Φ = BS* cos(a)$$\Phi$$ = $$BS\cdot cos(a)$$
BS* cos(a) = Φ$$BS\cdot cos(a)$$ = $$\Phi$$
cos(a) =
$$cos(a)$$ = $$\frac{\Phi}{BS}$$
| Φ |
| / BS |
a = arccos(
)$$a$$ = $$arccos(\frac{\Phi}{BS})$$
| Φ |
| / BS |